Find the value of k of x-3 is a factor of kx^3-kx^2+3kx-k
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Let, p(x) = kx³ - kx² + 3kx - k
By factor theorem..
If (x - 3) is a factor of p(x) then p(3) = 0
➡ k(3)³ - k(3)² + 3k(3) - k = 0
➡ 27k - 9k + 9k - k = 0
➡ 26k = 0
➡ k = 0 - 26
➡ k = - 26
Therefore, the value of k is " -26 ".
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