find the value of k. please on paper
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Note: Sorry, I don't have any pen and paper.
Given Equation is x^2 + k(2x + k - 1) + 2 = 0
x^2 + 2kx + k(k - 1) + 2 = 0
Given that the equation has real and equal roots.
D = 0
(2k)^2 - 4(1)(k(k - 1) + 2) = 0
4k^2 - 4(k^2 - k + 2) = 0
4k^2 - 4k^2 + 4k - 8 = 0
4k - 8 = 0
4k = 8
k = 8/4
k = 2.
Therefore the value of k = 2.
Hope this helps!
Given Equation is x^2 + k(2x + k - 1) + 2 = 0
x^2 + 2kx + k(k - 1) + 2 = 0
Given that the equation has real and equal roots.
D = 0
(2k)^2 - 4(1)(k(k - 1) + 2) = 0
4k^2 - 4(k^2 - k + 2) = 0
4k^2 - 4k^2 + 4k - 8 = 0
4k - 8 = 0
4k = 8
k = 8/4
k = 2.
Therefore the value of k = 2.
Hope this helps!
siddhartharao77:
If possible brainliest it.
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Hope this helps :))
I have done it on notebook
I have done it on notebook
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