find the value of k quadratic equation 9x2-3kx+k=0 has equal roots
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Answered by
213
Answer:
k = 4
Step-by-step explanation:
Our given equation is :
9 x² - 3 k x + k = 0
Comparing with a x² + b x + c = 0 we get :
a = 9
b = - 3 k
c = k .
Whenever we are told that the equation has equal roots then :
b² = 4 a c
This method can be used effectively to calculate the value of k .
( - 3 k )² = 4 ( 9 ) ( k )
⇒ 9 k² = 36 k
⇒ k² = 36 k / 9
⇒ k² = 4 k
⇒ k = 4
The value of k is 4 .
NOTE :
If the equation had real and unequal roots , then :
b² > 4 ac
If the equation had imaginary roots then :
b² < 4 ac
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