Math, asked by gsrao3469gmailcom, 1 year ago

find the value of k quadratic equation 9x2-3kx+k=0 has equal roots

Answers

Answered by Anonymous
213

Answer:

k = 4


Step-by-step explanation:


Our given equation is :


9 x² - 3 k x + k = 0


Comparing with a x² + b x + c = 0 we get :

a = 9

b = - 3  k

c = k .


Whenever we are told that the equation has equal roots then :

b² = 4 a c


This method can be used effectively to calculate the value of k .


( - 3 k )² = 4 ( 9 ) ( k )

⇒ 9 k² = 36 k

⇒ k² = 36 k / 9

⇒ k² = 4 k

⇒ k = 4


The value of k is 4 .

NOTE :

If the equation had real and unequal roots , then :

b² > 4 ac


If the equation had imaginary roots then :

b² < 4 ac

Answered by gayathrijohns03
126
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