find the value of k quadratic equations 9xsqaure-3kx+k=0
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If the equation have equal roots then it's discriminant will be equal to Zero
that is D = 0
And D = b² - 4ac
Here
a = 9
b = -3k
c = k
D = b² - 4ac
0 = ( - 3k )² - 4 × 9 × k
0 = 9k² - 36 k
0 = 9k ( k - 4 )
• 9k = 0
k = 0
• ( k - 4 ) = 0
k = 4
So ,
For both the value of k the equation have equal roots ...
that is D = 0
And D = b² - 4ac
Here
a = 9
b = -3k
c = k
D = b² - 4ac
0 = ( - 3k )² - 4 × 9 × k
0 = 9k² - 36 k
0 = 9k ( k - 4 )
• 9k = 0
k = 0
• ( k - 4 ) = 0
k = 4
So ,
For both the value of k the equation have equal roots ...
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