find the value of k s.t that 5/2is a root of the quadratic equation 14x^2-27x+k=0
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Answer:
Step-by-step explanation:
Substitute the value of X i.e 5/2
14×5/2^2-27×5/2+k=0
14×25/4-135/2+k=0
7×25/2-135/2+k=0
175/2-135/2+k=0
40/2+k=0
20+k=0
K=-20
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