Question

find the value of k so that 8 K + 46 K - 2 and 2 k + 7 will form an ap​

Answer 1

Step-by-step explanation:

If a, b, c are 3 consecutive terms of an AP, the a+c=2b

=> 8k+4+2k-7=2*(6k-2)

=>10k-3=12k-4

=>k=1/2

thus the terms are 8,1 and -6

Answer 2

Let 8k+4, 6k-2 and 2k-7 be 3 consecutive terms of an AP.

= (6K-2)-(8K+4) = (2K-7) - (6K-2)

= 6K-2-8K-4= 2K-7-6K +2

= -2K-6 = -4K-5

= 2K = 1

K = 1/2