Find the value of k so that 8k plus 4, 6k-2 and 2k plus 7 will form an A.P
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here CD is. = -2(k+3)
it is not In ap.
it is not In ap.
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As 8k+4, 6k-2 and 2k+7 are forming A.P they maintain common difference
6k-2-(8k+4)=2k+7 -(6k-2)
6k-2-8k-4=2k+7 -6k+2
-2k-6=-4k+9
2k=15
k=7.5
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