find the value of k, so that each equation will have real and equal roots
x^2 +kx +6 = 0
Answers
Answered by
1
Answer:
Step-by-step explanation:
By disciminant
b²-4ac=0
k²-4(6)(1)=0
k²=24
k=√24
k=2√6,-2√6
gargnakul67:
Mark it brainliest
Answered by
1
Answer:
Step-by-step explanation:
By disciminant
b²-4ac=0
k²-4(6)(1)=0
k²=24
k=√24
k=2√6,-2√6
Similar questions