Math, asked by imrani1, 1 year ago

find the value of k, so that each equation will have real and equal roots

x^2 +kx +6 = 0

Answers

Answered by gargnakul67
1

Answer:

Step-by-step explanation:

By disciminant

b²-4ac=0

k²-4(6)(1)=0

k²=24

k=√24

k=2√6,-2√6


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Answered by gargnakul67
1

Answer:

Step-by-step explanation:

By disciminant

b²-4ac=0

k²-4(6)(1)=0

k²=24

k=√24

k=2√6,-2√6

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