Question

Find the value of k so that each of following equation may have x = 1 and y = 2 as a solution.
3x + ky = 6
2x + 3y = k​

Answer 1

x=1

y=2

k=?

(I)- 3x+Ky =6

3+2k=6

2k=6-3

2k=3

k=3/2

(ii)-2x+3y=k

2+6=k

8=k