Question

find the value of 'k',so that k+2, 4k-6 and 3k-2 are the three consecutive terms of an A P

Answer 1

Step-by-step explanation:

In this A.P

k+2 , 4k-6 , 3k-2

a = k + 2

d = A2 - A1 = A3 - A2

(4k-6) - (k+2) = (3k-2) - (4k-6)

4k - 6 - k - 2 = 3k - 2 - 4k + 6

3k - 8 = -k + 4

4k = 12

k = 3