Math, asked by yadavsai475, 11 months ago

find the value of k so that k+2,4k+6and 3k-2are in ap​

Answers

Answered by sunny176127
2

Answer:

k=-3

Step-by-step explanation:

when it is a.possible the condition is

b=a+c/2

4k+6=k+2+3k-2/2

=4k/2

=2k

4k+6=2k

4k-2k=-6

2k=-6k

k=-6/2

k =-3

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