find the value of k so that k+2,4k+6and 3k-2are in ap
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Answer:
k=-3
Step-by-step explanation:
when it is a.possible the condition is
b=a+c/2
4k+6=k+2+3k-2/2
=4k/2
=2k
4k+6=2k
4k-2k=-6
2k=-6k
k=-6/2
k =-3
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