Find the value of k, so that polynomial 3−32−−3has one factor+3.
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Question :-Find the value of k so that the polynomial x3+ 3x2-kx-3 has one factor as x+3
Answer:
k =3/3 = 1
Step-by-step explanation:
x+3 =0
x=-3
p(x) = x3+3x2-kx -3
p(-3) = (-3)3 + 3(-3)2 -k(-3) -3 = 0
= -27 +27 +3k- 3 = 0
= 3k-3 = 0
= 3k =3
= k =3/3 = 1
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