Find the value of k so that polynomial x^3 +3x^2-kx-3 has one factor x+3
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6
x+3=0
x=-3
x^3+3x^2-kx-3
0=(-3)^3+3(-3)^2-k*(-3)-3
0=-27+3*9+3k-3
0=-27+27+3k-3
0=3k-3
3=3k
3/3=k
k=1
x=-3
x^3+3x^2-kx-3
0=(-3)^3+3(-3)^2-k*(-3)-3
0=-27+3*9+3k-3
0=-27+27+3k-3
0=3k-3
3=3k
3/3=k
k=1
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1
hope u got what u want....
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