Math, asked by shivajamar015, 16 days ago

find the value of k, so that polynomial x^3+3x^2-kx-3 has one factor as x+3.​

Answers

Answered by guptaumas99
2

Step-by-step explanation:

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Answered by siddiqueofficial66
2

Step-by-step explanation:

x+3=0

x=-3

p(x) = x3+3x2-kx -3

p(-3) = (-3)3 + 3(-3)2 -k(-3) -3 = 0

= -27 +27 +3k- 3 = 0

= 3k-3 = 0

= 3k =3

= k =3/3 = 1

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