Question

find the value of k so that PQ will be parallel to Rs where p ( 2, 4 ) (3,6) R(8,1 )and S(10,k)​

Answer 1

Answer:

K=5

Step-by-step explanation:

Given P(2,4)  Q(3,6) R(8,1) S(10,K)

PQ ll RS

SO

Slope of PQ=Slope of RS

6-4/3-2=K-1/10-8

2/1=K-1/2

K-1=4

K=5

Answer 2

The value of k is 5

Solution:

Given that,

PQ parallel to RS

If two lines are parallel, then their slopes must be equal

Slope of PQ = Slope of RS

Slope is given as:

$m = \frac{y_2-y_1}{x_2-x_1}$

Slope of PQ

P( 2, 4 )

Q (3,6)

$Slope = \frac{6-4}{3-2}\\\\Slope = 2$

Slope of RS

R(8, 1 )

S(10, k)

$Slope = \frac{ k - 1}{10- 8 }\\\\Slope = \frac{k - 1 }{2}$

Since both slopes are equal,

$2 = \frac{k - 1}{2}\\\\k-1 = 4\\\\k = 5$

Thus value of k is 5

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