find the value of k so that quadratic equation 3 x square minus 2 k x + 12 has equal roots
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Answer:
When we want equal roots then,
D = 0
So b square - 4ac = 0
In the given quadratic equation,
a = 3, b= - 2k, c = 12
Putting the values,
(-2k) square - 4(3)(12) = 0
4k square - 144 = 0
4k square =144
4k = Root 144
4k = 12
k = 12/4 = 3
Hence, k = 3.
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