Question

Find the value of k so that the difference of the rules at x square - 5 x + 3 k - 1 is equal to zero is 11

Answer 1

$\huge \text {Solution -}$


$= > {x}^{2} - 5x + 3k - 1 = 0 \\ = > {(11)}^{2} - 5 \times (11) + 3k - 1 = 0 \\ = > 121 - 55 + 3k - 1 = 0 \\ = > - 66 + 3k - 1 = 0 \\ = > 63k - 1 = 0 \\ \\ then \\ we \: find \: value \: of \: k \\ \\ = > 63k - 1 = 0 \\ = > 63k = 1 \\ = > k = \frac{1}{63} \: answer$


$\huge {Be} ^ {Brainly}$