Question

find the value of k so that the equation 2 x^2 - 3p x + 5 Q = 0 has one root which is twice than other​

Answer 1

Step-by-step explanation:

Here is your answer hope it helps you please mark as brainliest

Answer 2

Correct Question

Find the value of Q so that the equation 2 x² - 3px + 5q = 0 has one root which is twice than other.

Answer

q = p²/5

Explanation

Quadratic equation = 2x² - 3px + 5q = 0

Here, me denote alpha by M and beta by N which are zeros. Also, a = 2, b = -3p and c = 5q

Sum of roots = -b/a

→ M + N = -(-3p)/2

→ M + N = 3p/2

According to question,

One root is twice the another. So, N = 2M

→ M + 2M = 3p/2

→ 3M = 3p/2

→ M = p/2

So, N = 2(p/2) = p

Product of roots = c/a

→ MN = 5q/2

Substitute value of M and N

→ (p/2)(p) = 5q/2

→ p²/2 = 5q/2

2 throughout cancel

→ p² = 5q

→ p²/5 = q

→ q = p²/5