Question

Find the value of k so that the equation 3k2 + kx + 2 has equal roots

Answer 1

Answer:

2√6

Step-by-step explanation:

Here your equation is 3k^2+kx+2, and. it has equal roots...

If it has equal roots then the value of d that is discriminant will be 0....

We know that d=b^2-4ac

It can be written as b^2-4ac = 0

put the values...

a=3, b=k, and c=2

therefore, k^2 - 4*3*2 = 0

k^2 - 24 = 0

and k^2 = 24

so, k will be √24 that can also be written as 2√6

so k=2√6...

hope it helped you... stay blessed...