Find the value of K, so that the equation (k-1)x2
-3x+1=0 have equal roots
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Answer:
(k-1) x² - 3x + 1 = 0 ---------------------------have equal rooots
therefore, D= 0
b² - 4ac = 0
b² = 4ac
a = (k-1) , b = -3 , c = 1
(-3)² = 4 × ( k-1 ) × 1
9 = 4k - 4
9 + 4 = 4k
therefore , 4k = 13
k = 13/4
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