Question

find the value of k so that the equation kx square+6x+1=0 has equal rots​

Answer 1

Step-by-step explanation:

This is the form ax

2

+bx+c=0

Here a=k,b=6,c=1

Δ=b

2

−4ac

Since the roots are equal, discriminant=b

2

−4ac=0.

Therefore, (6)

2

−4×k×1=0

⇒36−4k=0

⇒4k=36

⇒ k=

4

36

=9

⇒ k=9

Answer 2

Step-by-step explanation:

kx²+6x+1=0

a=k b=6 c=1

D=b²-4ac

0=6²-4×k×1

0=36-4k

-36 = -4k

-36/-4=k

9=k

k =9