find the value of k so that the equation X + 2 Y = - 7 , 2 X + K Y + 14 = 0 will represent coincident lines.
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the value of k is 4 in the above pair of equation
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(1)
Given Equation is x + 2y = -7
= > x + 2y + 7 = 0
On comparing with a1x^2 + b1x + c1 = 0, we get
a1 = 1, b1 = 2, c1 = 7.
(2)
Given Equation is 2x + ky + 1 = 0
On comparing with a2x^2 + b2x + c2= 0, we get
a2 = 2, b2 = k, c2 = 14.
Now,
Given that the Equation represents coincident lines.
= > (a1/a2) = (b1/b2) = (c1/c2)
= > (1/2) = (2/k) = (7/14)
= > (1/2) = (2/k) = (1/2)
= > (1/2) = (2/k)
= > k = 2 * 2
= > k = 4.
Therefore the value of k = 4.
Hope this helps!
Given Equation is x + 2y = -7
= > x + 2y + 7 = 0
On comparing with a1x^2 + b1x + c1 = 0, we get
a1 = 1, b1 = 2, c1 = 7.
(2)
Given Equation is 2x + ky + 1 = 0
On comparing with a2x^2 + b2x + c2= 0, we get
a2 = 2, b2 = k, c2 = 14.
Now,
Given that the Equation represents coincident lines.
= > (a1/a2) = (b1/b2) = (c1/c2)
= > (1/2) = (2/k) = (7/14)
= > (1/2) = (2/k) = (1/2)
= > (1/2) = (2/k)
= > k = 2 * 2
= > k = 4.
Therefore the value of k = 4.
Hope this helps!
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