Question

Find the value of k so that the following equation has infinite solution 3x-y-5=0,6x-2 y-k=0

Answer 1

a1÷a2=b1÷b2=c1÷c2
3÷6=-1÷-2= -5 ÷ -k
1/2 = 1/2 = 5/k
k=5×2
k=10

Answer 2

Answer:

The value of k is 10.

Step-by-step explanation:

The given equations are

$3x-y-5=0$

$6x-2y-k=0$

These equation has infinite solution if

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

$\frac{3}{6}=\frac{-1}{-2}=\frac{-5}{-k}$

$\frac{1}{2}=\frac{5}{k}$

$k=10$

Therefore, the value of k is 10.