Math, asked by Pompi3728, 1 year ago

Find the value of k so that the following equations has infinitely many solutions 3x-y-5=0,6x-2y+k=0

Answers

Answered by swatibhargav
5
for the infinitely many sol.
A1/A2 = B1/B2 = C1/C2 _ {1}
where A1=3&A2=6
B1=1&B2=(-2)
C1=(-5)&C2=k

from eq.(1)
3/6=1/(-2)=(-5)/k
3/6=1/(-2) & "1/(-2)=(-5)/k"

cross multiply the inverted commas eq.
k=(-5)×(-2)
k=10
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