Find the value of k so that the following system of equations has no solution
3x-y-5=0 and 6x-2y+k=0 (3 marks ) Solve here itself.....
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Answer:
k= -10
Step-by-step explanation:
(3x-y=5) ×2 ....................... 1
(6x-2y= -k) × 1 ..................... 2
1+2
10 +k= 0
k= -10
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