Question

find the value of k so that the following system of equations has no solution 3x-y-5=0,6x-2y+k=0​

Answer 1

Answer:

k=-10

Step-by-step explanation:

a₁/a₂=b₁/b₂ ≠ c₁/c₂

Given Equation

3x-y-5=0 , 6x-2y+k=0

3x/6x=-5/k

3k=-30

k=-10

Answer 2

Answer:

Answer:

k=-10

Step-by-step explanation:

Step-by-step explanation:

a₁/a₂=b₁/b₂ ≠ c₁/c₂

Given Equation

3x-y-5=0 , 6x-2y+k=0

3x/6x=-5/k

3k=-30

k=-10