Question

Find the value of 'k' so that the following system of
equations has no solution.
3x - y = 5 and 6x - 2y + k = 0​

Answer 1

Answer:

Step-by-step explanation:

Given two equations, 3x – y – 5 = 0 (i.e) 3x - y = 5    …. (1)

6x - 2y – k = 0 (i.e) 6x - 2y = k    …. (2)

Divide equation (2) by 2, it becomes, 3x – y =  … (3)

From equation (1) and (3) LHS are equal, hence consider RHS