Question

find the value of k so that the following system of equations has a unique solution : x-2y=3 ; 3x + ky = 1​

Answer 1

Answer:

k is any other than -6

Step-by-step explanation:

if unique solution then

a1/a2 ≠ b1/b2

here a1 = 1,a2= 3

b1=-2,b2=k

here

a1/a2= 1/3

b1/b2= -2/k

therefore 1/3≠-2/k

so k≠-6

there fore k can be any other value except -6

so k is 1

I have given u step wise answer

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Answer 2

Step-by-step explanation:

x-2y-3=0. .......1

3x+ky+1=0. ........2

a¹=1 b¹=-2 c¹=-3

a²=3 b²=k c³=4

we known that

a¹/a² ≠ b¹/b²

than,

1/3≠-2/k

k=-6