Question

find the value of k so that the following
System of equations has no Solution
3x-y-5=0 ,6x-2y+k=0​

Answer 1

Answer:

-10

Step-by-step explanation:

3x-y= 5 & 6x-2y= -k

by comparing both the equations we get

k= -10

Answer 2

GIVEN

We are give a system of two linear equations

3x - y -5=0 and 6x - 2y + k =0

TO FIND

We need to find the value of k for which the system has no solution

THEORY

For the condition of no solution , A1/A2 = B1/B2 ≠ C1/C2

SOLUTION

==> 3/6 = 1/2 ≠ -5/K

==> 1/2 ≠ -5/K

==> K = -10