Find the value of k so that the line 2 x-3 y=9 and k x-9 y=18 will be parallel
raminder1:
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Answered by
5
see condition for parallel lines is:--
a1/a2 = b1/b2 ≠c1/c2
l------------------l
taking this....
2/k = -3/-9
2/k =1/3
2*3 = k
k = 6
a1/a2 = b1/b2 ≠c1/c2
l------------------l
taking this....
2/k = -3/-9
2/k =1/3
2*3 = k
k = 6
Answered by
5
2x - 3y = 9 → y = (2/3) x - 3
kx - 9y = 18→ y = (k/9) x - 2
Parallel = Same Slope
(2/3) = (k/9)
k = 6
kx - 9y = 18→ y = (k/9) x - 2
Parallel = Same Slope
(2/3) = (k/9)
k = 6
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