Question

Find the value of k so that the line 2x-3y=9 and kx-9y=18

Answer 1

Answer:

hey mate your answer is...

Step-by-step explanation:

$2x-3y=9 \\ kx-9y=18 \\ 2kx {}^{2} + 12y = 18 \\ kx {}^{2} + 12y = 18 - 2 \\ kx {}^{2} + 12y = 16..... \\ k = x {}^{2} + 12y - 16 = 0.... \\ hope \: its \: helps.....$

Answer 2

$\red{\large{\underline{\underline{\star\:{Given:-}}}}}$

Find the Value of k so, that the line 2x - 3y = 9 and kx - 9y = 18.

$\red{\large{\underline{\underline{\star\:{Answer:-}}}}}$

$\implies \sf\frac{a_1}{a_2} = \frac{b_1}{b_2} \\ \\ \implies \frac{2}{k} = \frac{ \cancel3}{ \cancel9} \\ \\ \implies \frac{2}{k} = \frac{1}{3} \\ \\ \implies k = 6.$

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