Question

Find the value of K so that the pair of linear equation Kx-2y=3 and 3x + y=5 has a unique solution

Answer 1

the value of k must not equal to -6.

Answer 2

Answer: The value of k will be $k\neq -6$

Step-by-step explanation:

Since we have given that

kx-2y=3

3x+y=5

Since it has unique solution, that means they are intersecting lines.

So, the condition of intersecting lines is :

$\frac{a_1}{2}\neq \frac{b_1}{b_2}\neq \frac{c_1}{c_2}\\\\\frac{k}{3}\neq \frac{-2}{1}\neq \frac{3}{5}\\\\\frac{k}{3}\neq \frac{-2}{1}\\\\-6\neq k$

Hence, the value of k will be $k\neq -6$