Question

Find the value of k so that the point (2,5) lies on the line kx+3y=1.........​

Answer 1

Answer:

put the value of x is 2

and, the value of y is 5

kx+3y=1

k×2+3×5=1

2k+15=1

2k=1-15

2k=-14

k=-14/2

k=-7

Answer 2

Answer:

k= -7

(2,5) satisfy the eqn of Kx+3y=1

x=2, y=5

K×2+3×5=1

2K+15=1

2K=-14

K=-7