Question

Find the value of k so that the point (3,k)lies on the line represented by the equation 2x-3y=5

Answer 1

x=3
y=k
2(3)-3(k)=5
6-3k=5
-3k=5-6
-3k=-1
k=-1/-3
k=1/3

Answer 2

Answer:

The value of k is $\frac{1}{3}$

Step-by-step explanation:

The given equation is $2x-3y=5$.

It is given in the question that the point (3,k) lie on the line $2x - 3y = 5$.

Now, Substitute $x=3$ and $y=k$ in the given equation, we get,

$2x-3y=5\\2\times3-3\times k=5\\6-3k=5$

Add ($3k-5$) both the side and get,

$6-3k+3k-5=5-5+3k\\ 6-5=3k$

Divide 3 by both the side and get,

$k=\frac{1}{3}$.

The value of k is $\frac{1}{3}$ so that the point $(3,k)$ lies on the line represented by the equation.

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