find the value of k so that the points A(-2,3) B(3,-1) and C(5,k) are collinear
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Answered by
54
Hey,
Thanks for asking this question.
Three collinear points are,
•A(-2,3) = (x1,y1)
•B(3,-1) = (x2,y2)
•C(5,k) = (x3,y3)
We know that given three points are collinear if and on if,
[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)] = 0
=> [-2(-1-k) + 3(k-3) + 5{(3-(-1))}]= 0
=> [2(1+k) +3(k-3) + 5(3+1)] = 0
=> (2 + 2k + 3k - 9 + 20) = 0
=> 5k + 13 = 0
●=> k = -13/5
●●●Hope My Answer Helped.
Thanks for asking this question.
Three collinear points are,
•A(-2,3) = (x1,y1)
•B(3,-1) = (x2,y2)
•C(5,k) = (x3,y3)
We know that given three points are collinear if and on if,
[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)] = 0
=> [-2(-1-k) + 3(k-3) + 5{(3-(-1))}]= 0
=> [2(1+k) +3(k-3) + 5(3+1)] = 0
=> (2 + 2k + 3k - 9 + 20) = 0
=> 5k + 13 = 0
●=> k = -13/5
●●●Hope My Answer Helped.
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