Find the value of k, so that the quadratic equation K²X²-2(K-1)x + 4 = 0 has equal roots
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Step-by-step explanation:
ANSWER
(4−k)x
2
+2(k+2)x+(8k+1)=0 for equal roots, D=0
a=(4−k),b=2k+4,c=8k+1, D=b
2
−4ac
D=(2k+4)
2
−4(8k+1)(4−k)
O=4k
2
+16+16k−4(32k−8k
2
+4−k)
O=4k
2
+16k+16−128k+32k
2
−16+4k
O=36k
2
−108k
O=k(36k−108)
∴k=0,k=3
36k=108
k=3.
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