Question

Find the value of k so that the quadratic equation kx (3x − 10) + 25 = 0, has two equal roots

Answer 1

Answer:

Expanding it gives:

3kx^2-10kx+25=0

To obtain two equal roots, the discriminant must equal zero.

Discriminant=(-10k)^2-4(3k)(25)=100k^2-300k

∴100k^2-300k=0

100k(k-3)=0

100k=0 or k-3=0

k=0, k=3

Since k=0 is not plausible, k=3 is the solution.

Hope this helps :)

Step-by-step explanation:

Answer 2

Given:

kx (3x − 10) + 25 = 0

To Find:

The value of k

Explanation:

Expanding it gives:

(3kx)²-10kx+25=0

To obtain two equal roots, the discriminant must equal zero.

Discriminant=(-10k)²-4(3k)(25)=(100k)²-300k

Then (100k)²-300k=0

100k(k-3)=0

100k=0 or k-3=0

k=0, k=3

Answer = 0,3.