Question

Find the value of k so that the quadratic equation kx(x--2)+5=0 has equal roots

Answer 1

Answer:

-1

Step-by-step explanation:

on putting -1 in the place of x we get 5 which has equal zeros

Answer 2

Answer:

$\huge\mathbb\red{ k = 10}$

Step-by-step explanation:

TO HAVE EQUAL ROOTS:-

b² - 4ac = 0

Given:

$\bf\huge\green{5x² -2kx + 20 = 0}$

Solution

$\sf\bf {b}^{2} - 4ac = 0 \\ \\ \sf\bf { (- 2k)}^{2} - 4(5)(20) = 0 \\ \\ \sf\bf 4 {k}^{2} - 400 = 0 \\ \\ \bf 4 {k}^{2} = 400 \\ \\ \bf {k}^{2} = \frac{400}{4} \\ \\ \bf {k}^{2} = 100 \\ \\ \bf k = \sqrt{100} \\ \\ \bf\huge \fbox\purple{k = 10 \: answer}$

$\huge\mathrm\blue{Hence\: the\: value\: of \:K \: is \: 10}$

$\sf\huge\underbrace\purple{GalaxyFanFan}$