Question

find the value of K so that the
quadratic equation Kx( x-2) + 6 =0
have two equal roots​

Answer 1

Given that,

find the value of K so that thequadratic equation Kx(x-2) + 6 =0

➡ kx(x - 2) + 6 = 0

➡ kx² - 2kx + 6 = 0

Let,

• a = k
• b = -2k
• c = 6

By using discrimination, we get the value of k

➡ b² - 4ac = 0

➡ (-2k)² - 4(k)(6) = 0

➡ 4k² - 24k = 0

➡ 4k(k - 6) = 0

➡ (k - 6) = 0/4k

➡ (k - 6) = 0

➡ k = 0 + 6

➡ k = 6

∴ The value of k is “ 6 ” .

Step-by-step explanation:

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Answer 2

Answer:

k=6

Step-by-step explanation:

kx(x-2)+6=0

kx^2-2kx+6=0 it is in the form ofax^2+bx+c=0

a=k,b=-2k,c=6

if discriminant equals to zero then the quadratic equation have equal roots so

discriminant (d)=b^2-4ac=0

(2k)^2-4(k)(6)=0

(2k)^2-24k=0

4k^2=24k

4k=24

k=6