Question

Find the value of 'k' so that the quadratic equation kx² +2x +k=0 has real and equal roots​

Answer 1

Answer:

k = ± 1

Step-by-step explanation:

$kx^2 + 2x + k = 0$

a = k, b = 2, c = k

As the equation has real and equal roots,

D = 0.

$D = b^2 - 4ac$

$0 = 2^2 - 4 (k)(k)$

$0 = 4 - 4k^2$

$4(1-k^2) = 0$

$1-k^2 = 0$

$k^2 = 1$

$k = ± 1$

k = ± 1

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