Find the value of k so that the quadratic equation x^2-2x(1+3k)+7(3+2k)=0 has two equal roots.
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Hello
we have given equation is
x² + 2x(1 + 3k) +7(3 + 2k) = 0
or
x² + 2(1 + 3k)x +7(3 + 2k) = 0
roots are equal
we have to find the value of k =?
now
we know that an equation have equal roots if and only if D = 0
=> b² -4ac = 0
here comparing the equation with
ax² + bx + c = 0
here
a= 1, b = 2(1 + 3k) and c= 7(3 + 2k)
now
b² - 4ac = 0
= [ 2(1 + 3k) ]² - 4 ×1×7(3 + 2k) = 0
= 4×(1 + 3k)² - 4×7(3 + 2k) = 0
= 4(1 + 9k² + 6k) - 4(21 +14k) =0
= (1 + 9k² + 6k) - (21 +14k) =0
=> 9k² - 8k -20 = 0
now solving the equation we get
= 9k² - 18k + 10k - 20 = 0
= 9k( k- 2) + 10(k -2) =0
=> 9k +10=0 and k -2 = 0
=> k = -10/9 and 2 answer
✯✯ hope it helps ✯✯
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