Question

find the value of K so that the quadratic equation x2-4x+k=0 has equal roots.

Answer 1

${x}^{2} - 4x + k = 0 \\ a = 1 \: \: \: b = - 4 \: \: \: c = k \\ if \: it \: is \: equal \: root\\ then \\ discriminant = 0 \\ {b}^{2} - 4ac = 0 \\ { - 4}^{2} - 4 \times 1 \times k = 0 \\ 16 - 4k = 0 \\ 16 = 4k \\ k = \frac{16}{4} \\ k = 4$
_____________________________

THANKS ☺️

Answer 2

हल- समीकरण

${x}^{2} - 4x + k = 0$

यहाँ

$a = 1 \: \: \: \: \: \: \: \: \: \: b = -4 \: \: \: \: \: \: \: \: \: \: c = k$

जब मूल बराबर होते हैं तब प्रतिबंध

${b}^{2} = 4ac \\ \\ \\ ( - 4) {}^{2} = 4 \times 1 \times k \\ \\ 4k = 16 \\ \\ \\ k = 4$