Question

Find the value of k so that the quadratic equations 3x2-2kx+12=0 has equal roots

Answer 1

for equal roots D=0
i.e.
${b}^{2} - 4ac = 0 \\ 4 {k}^{2} - 144 = 0 \\ 4 {k}^{2} = 144 \\ {k}^{2} = \frac{144}{4} \\ k = + - \sqrt{ \frac{144}{4} } \\ k = + - \frac{12}{2} \\ k = + - 6$

Answer 2

Answer:

Here is your answer...