Question

Find the value of k so that the quadratic has equal roots: 2x^2-(k-2)x+1=0. Please give a detailed solution. Thank you.

Answer 1

Equation has equal roots then

$b {}^{2} - 4ac = 0$

a = 2 b= k - 2 c =1

$(k - 2) {}^{2} - 4(2)(1) = 0$

$k {}^{2} - 4k + 4 - 8 = 0$

$k {}^{2} - 4k - 4 = 0$

Solve above eq. you will get value of k.


Thanks