find the value of k so that the sequence 2k-5 k-4 10k-3
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Answer:
2k−1,7,11 are in
A.P
a
1
=2k−1
a
2
=7
a
3
=11
a
2
−a
1
=a
3
−a
2
7−(2k−1)=11−7
7−2k+1=4
8−2k=4
8−4=2k
4=2k
k=2
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