Math, asked by yuvi919447, 1 year ago

find the value of k so that the sum of the sum of the roots of the quadtric equation 3x^2+(2k+1)x-(k+4)=0 is equal to the products of the roots​

Answers

Answered by yuvsingh1705
1

f(x)=3x^2+(2k+1)x-(k+4)=0

Here, a=3

b=(2k+1)

c= -(k+4)

ATQ

Alpha +Beta=Alpha×Beta

-b/a=c/a

-b=c

-(2k+1)=-(k+4)

2k+1=k+4

3k=3

k=1

Hope it helps you...

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