Find the value of k so that the system of equations has no solution:
3x-y-5=0; 6x-2y-k=0
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Answer:
3x/6x = 1/2
-y/-2y = 1/2
-5/-k = ?
let put the value of k =10
-5/-10 = 1/2...
so the value of k will be 10....
hope it helps....
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