Question

Find the value of k so that the zeroes of the quadratuc polynomial 3x^2-kx+14 are in the ratio 7:6.

Answer 1

Step-by-step explanation:

let the zeroes of the polynomial be 7a and 6a

we know that

$\alpha + \beta = - b \div a$

So,7a+6a=k/3

13a=k/3.....(I)

and

$\alpha \beta = c \div a$

So,7a*6a=14/3

42a²=14/3

a²=1/9

a=1/3

So, if we put the value of a in the equation(i),

13/3=k/3

k=13