Question

find the Value of k so that the zeros of 3x2 - kx +14 are in the ratio of 7:6

Answer 1

5:4............................

Answer 2

Let the zeros be a & b
A/b=7/6
A=7b/6
Product of zeros =c/a
Ab=14/3
$7 {b}^{2} \div 6 = 14 \div 3$
${b}^{2} = 4$
B=2
On putting its value, a
A=7/3
Sum of zeros =-b/a
A+b=k/3
7/3+2=k/3
13/3=k/3
K=13