Question

find the value of 'k' so that the zeros of the quadratic polynomial 3x²-kx+14 are in the ratio of 7:6​

Answer 1

Answer:

As ratio is 7:6, let the roots are 7a and 6a.

Product of constant term/co.ef. of x^2

= > 7a * 6a = 14 / 3

= > 7*2*3 a^2 = 14/3

= > 3a^2 = 1/3

= > a^2 = 1/9

= > a = 1/3

Sum of roots = k/3

= > 7a + 6a = k/3

= > 21a + 18a = k

= > 39a = k

= > 39(1/3) = k

= > 13 = k

Required value of k is 13.